Handbook of Cosmetic Science and Technology, Third Edition

Ebook introduction of knowledge about the technology in the manufacture of cosmetics and testing physical properties of the chemical in the manufacture of dosage formulations of cosmetics are increasingly made ​​by pharmaceutical companies.
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METHOD ALKALIMETRI

1. The manufacture of aqueous ethanol
   mix 500 ml 95% ethanol and 500 ml of pure water which is measured separatelyand the mixture was measured at 25, the volume of a mixture of 970ml.
2. manufacture of ethanol diluted neutral
   on a number of dilute ethanol add 2 - 3 drops of phenolphthalein and 0.1 N NaOH solution until there is a pale pink color.
3. making a solution of phenolphthalein
   200mg phenolphthalein dissolved in 60 ml of ethanol 90% add enough water until100ml
4. manufacture of carbon dioxide-free water
   pure water boil for 5 minutes or so, then covered with cotton fed Cao oxide carbon powder and let stand until cool and can not absorb carbon dioxide from the air
5. manufacture of 0.1 N NaOH solution
   number of NaOH dissolved in CO2-free water so that each 1000 ml solution containing 4.001 grams of NaOH
6. standardization of NaOH 0.1 N
     carefully weigh 400 mg of potassium biftalat previously been mashed and dried at120 * C for 2 hours, enter in the erlenmeyer, add 75 ml of CO2-free water, caperlenmeyer shake until dissolved. add 2 drops of phenolphthalein and titration with NaOH until there is a pink solid.
   
   one ml of 0.1 N NaOH is equivalent to 20.42 mg KHC8H4O4
   reaction:
   KHC8H4O4 + NaOH => KNaC8H4O4
   calculation:
   
   Normality of NaOH = mg KHC8H4O4: (ml NaOH x BM KHC8H4O4)
7. determination of drug levels of salicylic acid
   
   carefully weigh 500 mg, dissolved in 25 ml of aqueous ethanol that has beenneutralized with 0.1 N NaOH, add phenolphthalein and titrate with 0.1 N NaOH
   one ml of 0.1 N NaOH is equivalent to 13.81 mg of C7H6O3
   
   reaction:
   HOC6H4COOH + NaOH => H2O + HO.C6H4.COONA
   
   calculation
   levels of salicylic acid = (ml NaOH x N NaOH x 13.81) : (mg sample x 0.1) x 100%
8. Grafic concentration